
Texas Instruments
A modern alternative with higher current and low IQ, but requires layout changes for the 5-pin package.
The 78L33 is a classic 3.3V linear voltage regulator providing up to 100mA. While widely available, modern alternatives offer significant improvements in efficiency and size, but often require design modifications.
Many alternatives have lower max input voltage, posing an overvoltage risk.
Modern parts use different packages (e.g., SOT-23-5) and pinouts, requiring board redesign.
No direct drop-in replacement has been identified from the candidates. All require careful review of input voltage and pinout.
For new designs, select a modern LDO like the TPS7A24 series. For existing boards, finding a true pin-compatible replacement with a >=20V input rating is critical.
The primary risk is mismatched maximum input voltage and different package pinouts. Many modern LDOs have lower input voltage ratings than the 20V of the 78L33.

Texas Instruments
A modern alternative with higher current and low IQ, but requires layout changes for the 5-pin package.
| Feature / factor | 78L33 | TPS7A2433DBVR | XC6202P332MR | Alt 3 | Compatibility / risk |
|---|---|---|---|---|---|
| Voltage | 20V | 18V | 15V | 18V / 15V — Slightly lower max input voltage.; XC6202P332MR: Candidate has lower max input voltage. | |
| Package | SOT-23, TO-92, etc. | SOT-23-5 | SOT-23-3 | SOT-23-5 / SOT-23-3 — 5-pin package requires new layout and handling of EN pin.; XC6202P332MR: Package may not match application; pinout is different. | |
| Current | 100mA | 200mA | 150mA | 200mA / 150mA — Higher output current capability.; XC6202P332MR: Higher output current capability. | |
| Quiescent Current | 2mA | 2.0uA | 2.0uA | 2.0uA — Significantly lower quiescent current.; XC6202P332MR: Significantly lower quiescent current improves efficiency. |
The best alternative depends on your circuit's input voltage. For inputs below 15V, parts like XC6202P332MR offer better performance but require pinout changes. For higher voltages, a different search is needed.